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chemistry
Question by Joe52 (38)
Glucose = c6h12o6
Answer by chemteach (100)
Using stoichiometry, completely consuming 0. 1127 g of glucose by combustion with oxygen will produce a yield of 0. 1652 g of carbon dioxide.
Answer by BrianSJ (524)
Combustion of one mole (180 g) or glucose produces 264 (6*44) g of CO2, so you'd get. 1127 * (264/180) =. 1653 g of CO2.
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