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Question by Phantasmality (36)
Answer by shobby (42)
Each mole of chloral hydrate which weighs 165. 394g contains 3 moles of Cl. 1. 0g Cl / 35. 5 g/mol Cl = 0. 028 mols Cl. 0. 028 mols Cl / 3 = 0. 009 mols chloral H. 0. 009 mols chloral H * 165. 394 g/mol = 1. 48 grams chloral H.
Answer by reemasidz (61)
1. 55305 g of Chloral hydrate contains 1. 0 g Cl. since 165. 4 contains 106. 5 Cl, we have: 1. 0*(165. 4/106. 5)= 1. 55305 g of Cl by ratio method
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