What is an epsilon-delta proof of a limit?

Answer by  BrianSJ (524)

Allow a number n to approach x so that the absolute value of n-x is less than epsilon, some arbitrarily small number. Then the absolute value of f(n)-f(x) will be delta. For proof of a limit, you have to show that delta approaches zero as epsilon approaches zero.

Answer by  UpwardBoundPrecalcTutor (128)

An espilon-delta proof is a proof a limit exists based upon the definition of limit lim[x→a] f(x) = L if and only if for each е>0 there exists δ>0 suchthat |f(x)-L|<δ→→0<|x-a| add a comment