# Question #7801b

##### 1 Answer

Apr 4, 2017

#### Explanation:

We need to define even and odd functions:

#f# is an even function if#f(-x)=f(x)# .#f# is an odd function if#f(-x)=-f(x)# .

It's also useful to know that

We have:

#f(x)=x^2cos(x)#

Test this function by finding

#f(-x)=(-x)^2cos(-x)#

We already know that

#f(-x)=x^2cos(x)=f(x)#

Since