How do you show factor by grouping?

Answer by  minisudhakaran (77)

Factorize the given number using the prime numbers. Then take each prime number and count their numbers and give this number as its power.

Answer by  Helper28 (52)

You are given a set of numbers usually with a constant. Example 8x, 16x^2, 4x^3. With this set your job is to pull out the highest polynomial shared by all of them. In the example this would be 4x since that clearly is a part of each set so your left with: 2(4x), 4x(4x), x^2(4x).

Answer by  VB (361)

Given a polynomial to factor, break it into two or more groups. For each group, find the common factor and factor it out. If all the groups have a common factor, then you can factor the common factor out of all the groups and collect remaining terms into a group.

Answer by  MathTeacher (299)

To factor by grouping, you must start with 4 terms. Take the first two terms, and factor out the GCF, then do the same for the last two terms. Then factor out the common factor between the newly formed terms, often in the form of (x+a). Your finished product will resemble (x+a)(x+b) and your polynomial is now factored by grouping.

Answer by  stevenhuynh (86)

The common way is to re-arrange the terms and then factor. e.g. 4y^2 + 2x^2 + 3x + 2y = 4y^2 + 2y + 2x^2 + 3x = 2y(2y + 1) + x(2x + 3) Alternatively, you can skip the second step and write down in the margins: "... , by factor by grouping" or something similar.

Answer by  Kevin09 (16)

We can factorise a group by looking at the most common factor in that group. So Whenever a group if complex we have to simplify it may be by applying suitable laws (Example: distribution law) or formulas which will help you to get a factor.