What is the answer to (9x-4)(3x+2)?

Answer by  Clement (1453)

To answer this question you need to make three steps. First, open the parenthesis: 9x*3x + (-4)*3x + 9x*2 + (-4)*2. Then, make basic calculations 27x^2 - 12x + 18x - 8. Finally, you need to simplify the expression a little bit more to obtain the final answer: 27x^2 + 6x - 8.

Answer by  mamapuppy (241)

You use FOIL to multiply the two factors, which means multiply the First, Outer, Inner, then Last parts of each factor together. First - 9x*3x=27x2 (the 2 means squared) Outer - 9x*2=18x Inner - -4*3x=-12x Last - -4*2=-8 Then combine to get 27x2+6x-8

Answer by  Learner (350)

1) Multiply each term : 27x^2+18x-12x-8=0 27x^2+6x-8=0 2) 27x^2+6x-8=0 form of ax^2+bx+c=0 3) Using formula x=(-b+(SQRT(b^2-4ac)))/2a , x =(-b-(SQRT(b^2-4ac)))/2a and a=27,b=6,c=-8 we get x=4/9, x=-2/3

Answer by  Yazuser (52)

You just multiply the factors. (9x - 4)(3x + 2)= 27x(squared) + 18x - 12x -8. Simplifying: 27x(squared) + 6x - 8. When I write (squared) I mean that the x is multiplyid bi itself.