Answer by
amswplusone (652)

First note that x^2+2x+1=(x+1)^2, so sqrt(that) is x+1. Thus you're integrating x+1; raise the power of x by one and divide by the new exponent, ditto for 1, making it (1/2)x^2+x. Don't forget to add a constant! So you end up with (1/2)x^2+x+C, with C an arbitrary constant.